MedVision ad

Queries with Functions (1 Viewer)

Lukybear

Active Member
Joined
May 6, 2008
Messages
1,466
Gender
Male
HSC
2010
If f(x) = ax^2 + bx + c , find a,b,c so that f(1)=0, f(-1) = 0, f(-2) = 15



Ive got a=5, b=0, and c=-5. The answers were different tho, yet still right.
a=2, b=-3 and c=1. Im interested in why thats the case, and would HSC present such a question?
 
Last edited:

omniscience

Member
Joined
Aug 28, 2008
Messages
279
Gender
Undisclosed
HSC
N/A
If f(x) = ax^2 + bx + c , find a,b,c so that f(1)=0, f(-1) = 0, f(-2) = 15



Ive got a=5, b=0, and c=-5. The answers were different tho, yet still right.
a=2, b=-3 and c=1. Im interested in why thats the case, and would HSC present such a question?
i dun no how to do it

but 1 + 1 =2, keep that in mind. make sure ur basics are tight
 

kurt.physics

Member
Joined
Jun 16, 2007
Messages
840
Gender
Undisclosed
HSC
N/A
If f(x) = ax^2 + bx + c , find a,b,c so that f(1)=0, f(-1) = 0, f(-2) = 15



Ive got a=5, b=0, and c=-5. The answers were different tho, yet still right.
a=2, b=-3 and c=1. Im interested in why thats the case, and would HSC present such a question?
I also got the same answer as you, the textbook must be wrong. The answer they gave is wrong as it doesnt satisfy f(-1) = 0
 

Lukybear

Active Member
Joined
May 6, 2008
Messages
1,466
Gender
Male
HSC
2010
omg... im such a idiot. I check the answers against the equation and i thought it was right as well... Such silly mistakes...
 

Drongoski

Well-Known Member
Joined
Feb 22, 2009
Messages
4,255
Gender
Male
HSC
N/A
omg... im such a idiot. I check the answers against the equation and i thought it was right as well... Such silly mistakes...
If 2 quadratics have >= 3 points in common then they are the same quadratic; can't be 2 distinct ones. Besides f(-1) = 6 with the book's answer.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top