Please help!!! (1 Viewer)

[kwabon]

the experiment "finding g from a pendulum",
the graph which shows the relationship of T^2 and L, does it start from the origin???

because one of my teacher is saying that it does, whilst the other teacher from the other physics class says it does not...
wat should i do????

thanks so much for ur time.

 

[lolokay]

well you draw a line of best fit with your experimental data points, so it may or may not pass through the origin

 

[anon09]

Considering the equation T^2 = 4pi (l/g), when length is zero, T^2 would also be zero so I'd say that the graph would pass through the origin.

But since your teacher disagrees with another teacher, it could well be more complicated.

 

[youngminii]

I've done this. Technically when the length is zero, the pendulum cannot swing. Hence T would be undefined. However my teachers told us to ignore this and to just draw a graph starting from the origin, although they said you certainly wouldn't be marked down for drawing it with an open dot at the origin.

 

[kwabon]

I've done this. Technically when the length is zero, the pendulum cannot swing. Hence T would be undefined. However my teachers told us to ignore this and to just draw a graph starting from the origin, although they said you certainly wouldn't be marked down for drawing it with an open dot at the origin.

thats interesting, i just may use it... hopefully will get away with it.

well you draw a line of best fit with your experimental data points, so it may or may not pass through the origin

yeh i understand wat u say but, according to the equation, if l is 0, then the pendulum cannot swing and hence g will be undefined (as the other boser just said), but in your case when l=0 and the t^2 = a constant which is impossible.

but thanks for the help, u guys

 

[helper]

If you are measuring to the centre of mass it should go through the origin. In the real world, most people don't measure to the centre of mass, so there is an error and that is represented by the line not going through the origin.