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You have already tried finding the indefinite integral for all three of them?
Yes thats right and what did you get when you substituted (1,1)Is it y=ln (x^2+5x+4) + C
And then you substitute (1,1) to find C. But the solution is y=log (x^2+5x+4/10) +1
You subbed the x=1 in log((1)^2 + 5(1) + 4)?C=0
So y = log (x^2 +5x+4)
But the solution is as mentioned above y= log (x^2+5x+4/10) +1
Did you try turning it into reciprocal and then integrating it?AAah okay I get what I did wrong thanks now I need 9e
EvaluateOkay I got 9e finally but how is y(e) = e+1!??
I got y= 2+x -log x
So y(e) = 2+e-log e
What does loge (e) equate toOkay I got 9e finally but how is y(e) = e+1!??
I got y= 2+x -log x
So y(e) = 2+e-log e