Please help, mole and mass produced question. (1 Viewer)

[Shoom]

1.35g sodium carbonate and 1.35g copper nitrate were both placed into 2 separate beakers of water. These substances were then mixed together. What is the mass of the copper carbonate is formed?

Please show all working.

 

[Undermyskin]

n Na2CO3 = 1.35/ (45.98 + 12.01 + 48) = 0.01273705 mol = n CO3 (2-)

n Cu (NO3)2 = 1.35/ (63.55 + 28.02 + 96) = 0.0071973... = n Cu (2+)

Cu: CO3 = 1:1
--> n CuCO3 = n Cu (2+)
--> m CuCO3 = 0.0071973... * (63.55 + 12.01 + 48) = 0.889299994 = 0.889 g (3 s.f.)

 

[clintmyster]

n Na2CO3 = 1.35/ (45.98 + 12.01 + 48) = 0.01273705 mol = n CO3 (2-)

n Cu (NO3)2 = 1.35/ (63.55 + 28.02 + 96) = 0.0071973... = n Cu (2+)

Cu: CO3 = 1:1
--> n CuCO3 = n Cu (2+)
--> m CuCO3 = 0.0071973... * (63.55 + 12.01 + 48) = 0.889299994 = 0.889 g (3 s.f.)

can you assume that the copper is 2+ ?

 

[minijumbuk]

Unless it specifically says Copper (I), you must always assume it is Copper (II).
That goes for most, not all, transition metals as well.