Please carrotsticks or someone, help with final maths problem (1 Viewer)

[jackerino]

You typed to prove FBE is similar to FDE. Did you mean to prove FBC is similar to FDE?

yes I did. my mistake.

 

[Bozza555]

Is this what it looks like?

 

[jackerino]

View attachment 26061

Is this what it looks like?

YES!! Eggggsactly

 

[Bozza555]

for ii) i got k:l, not sure if its right though
and have you done i)?

 

[Carrotsticks]

 

[Carrotsticks]

You can save the image I've attached, then zoom in using whatever image-viewing program you have.

BTW for the first green line, disregard the "We must prove that XXXX". Forgot to rub that out.

Also in the second last green line, the first symbol should be FD, but the downstroke disappeared for some reason.

 

[Bozza555]

how did you attach the image like that without creating a link?

 

[jackerino]

You can save the image I've attached, then zoom in using whatever image-viewing program you have.

BTW for the first green line, disregard the "We must prove that XXXX". Forgot to rub that out.

Also in the second last green line, the first symbol should be FD, but the downstroke disappeared for some reason.

Thanks carrot! You're the best

 

[Carrotsticks]

how did you attach the image like that without creating a link?

[IMG*]link to the image[*/IMG]

 

[Bozza555]

[IMG*]link to the image[*/IMG]

ohh okay thanks!

 

[jackerino]

Ohh does anyone know that other question about "How many ways can a mixed doubles tennis match be played with 6 married couples, so that no husband and wife play in the same match?"

 

[Leffife]

Thanks carrot! You're the best

No need to say that since we already know he's the best. It's pointless saying something that has already been discovered.

 

[Carrotsticks]

Ohh does anyone know that other question about "How many ways can a mixed doubles tennis match be played with 6 married couples, so that no husband and wife play in the same match?"

What's to say that there isn't any same-sex marriage involved =)

There are 4 positions in a doubles tennis match.

First position could be anybody of the 12 (6 married couples = 12 people), so we have 12 choices.

Second position could be anybody EXCEPT their partner, so we have 10 choices. (Total 24 - 1 married couple = 10)

Third position could be anybody except the second and first person's partner, so we have 8 choices. (Total - 2 married couples = 8)

Fourth position could be anybody except the first, second and third person's partner, so we have 6 choices. (Total - 3 married couples = 6)

So therefore the number of mixed doubles tennis matches, such that there are no PARTNERS in the same match, is 12 x 10 x 8 x 6 = 5670.