UV light of frequency 7 x 1015 Hz falls on a photoemitter. Photoelectrons are emitted with kinetic energy equal to 9 x 10-19 J.
a)Calculate the work function of the emitter. I'm fine with this, just using KE = hf - W,, then rearranging. The answer is 3.74 x 10-18 J.
b)Calculate the stopping voltage of the emitter.
c) Find the threshold frequency, I'm fine with this, the answer is 5.64 x 1015 Hz.
Also, if u increase intensity of light on a photoemitterm does this increase the voltage or current in the external circuit connecting the cathode and anode? And what effect does increasing frequency have on voltage and current in the external circuit? I'd appreciate it if someone could clarify this for me.
a)Calculate the work function of the emitter. I'm fine with this, just using KE = hf - W,, then rearranging. The answer is 3.74 x 10-18 J.
b)Calculate the stopping voltage of the emitter.
c) Find the threshold frequency, I'm fine with this, the answer is 5.64 x 1015 Hz.
Also, if u increase intensity of light on a photoemitterm does this increase the voltage or current in the external circuit connecting the cathode and anode? And what effect does increasing frequency have on voltage and current in the external circuit? I'd appreciate it if someone could clarify this for me.
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