Permutation question (1 Viewer)

[boredofstudiesuser1]

A poker machine with 4 wheels and 20 symbols on each wheel has 5 aces on the first wheel, 4 aces on the second and 2 aces on each of the remaining wheels. What is the probability of 4 aces showing?

 

[InteGrand]

A poker machine with 4 wheels and 20 symbols on each wheel has 5 aces on the first wheel, 4 aces on the second and 2 aces on each of the remaining wheels. What is the probability of 4 aces showing?

Assuming independence of the wheels and that each symbol is equally likely to show up, it is (5/20)*(4/20)*(2/20)*(2/20).

 

[boredofstudiesuser1]

Assuming independence of the wheels and that each symbol is equally likely to show up, it is (5/20)*(4/20)*(2/20)*(2/20).

So the question isn't different to standard probability?

 

[InteGrand]

So the question isn't different to standard probability?

No, it's not.

 

[boredofstudiesuser1]

No, it's not.

Seeing 'InteGrand' as browsing my threads when I feel really stressed out about a question gives me so much hope.

Thank you so much.