Need help with a maths question. (1 Viewer)

[ManBearTank]

Differentiate 1/2(mx-x^2+b)(m^2+4b)^1/2 in terms of m

I can't get my head around it my answer doesn't match the teacher's answer =s

Thanks guys

 

[khorne]

So that's 1/[2(mx-x^(2)+b)(m^(2)+4b)^{1/4}]

Just use the product rule, and differentiate(internally) (m^2 +4b)^-1/2 with the chainrule.

 

[TheStallion]

@ManBearTank - Just in case you don't know the product rule:

(1st * deriv of 2nd) + (2nd * deriv of 1st)

Found this video for you too, to understand it better - YouTube - The Product Rule for Derivatives

 

[ManBearTank]

Thanks guys.

Yeh, i know all the rules, just that apparently the (m^2+4b)^1/2 is a constant because it doesn't have an x in it and therefore is 0 when you differentiate it =s

Just don't get that part.

 

[ninetypercent]

Thanks guys.

Yeh, i know all the rules, just that apparently the (m^2+4b)^1/2 is a constant because it doesn't have an x in it and therefore is 0 when you differentiate it =s

Just don't get that part.

that's weird. I thought we were differentiating in terms of m instead of x

 

[ManBearTank]

that's weird. I thought we were differentiating in terms of m instead of x

THat's what the question says... =s

 

[khorne]

What's the teacher's answer? If x and m are both variables, you will need to do this implicitly.