MedVision ad

need help for 1 SHM! (1 Viewer)

Mainoyi

Member
Joined
Mar 5, 2008
Messages
36
Gender
Female
HSC
2009
A particle moves along the x-axis. It starts from rest at the point x = 1. Its acceleration is given by: acceleration = −4(x + 1/(x^3). Find its velocity when it is half-way from its starting point to the origin.
 

Timothy.Siu

Prophet 9
Joined
Aug 6, 2008
Messages
3,449
Location
Sydney
Gender
Male
HSC
2009
A particle moves along the x-axis. It starts from rest at the point x = 1. Its acceleration is given by: acceleration = −4(x + 1/(x^3). Find its velocity when it is half-way from its starting point to the origin.
a= = −4(x + 1/(x^3)

vdv/dx= = −4(x + 1/(x^3)
1/2 v^2 = -2x^2 +2/x^2 +C
when v=0, x=1
-2+2+C=0
C=0

then, 1/2 v^2 = -2x^2 +2/x^2
so when x=1/2
1/2 v^2=-1/2 +8
v^2=15
v=+-root15
might've made a mistake.
 

Mainoyi

Member
Joined
Mar 5, 2008
Messages
36
Gender
Female
HSC
2009
a= = −4(x + 1/(x^3)

vdv/dx= = −4(x + 1/(x^3)
1/2 v^2 = -2x^2 +2/x^2 +C
when v=0, x=1
-2+2+C=0
C=0

then, 1/2 v^2 = -2x^2 +2/x^2
so when x=1/2
1/2 v^2=-1/2 +8
v^2=15
v=+-root15
might've made a mistake.

thanks heaps..
didn't notice that when x=1,v=0...
 

blake_ed

New Member
Joined
Oct 12, 2009
Messages
2
Gender
Undisclosed
HSC
2009
"v=+ - root15"
perhaps should be
v=-root15 as velocity is to the left, which is -ve
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top