MX 2 (2 Viewers)

[umm what]

x-2 - 5 / x-2

Nightweaver has 4 instead of 5

 

[seanieg89]

I've always thought lower case delta was used for smaller changes and upper case delta for larger changes lol.

Meh, so many people use different notation...but in most calculus books I've seen upper case delta is the standard when looking at difference quotients.

Lower case delta is used more in analysis-type arguments and at a higher level, in calculus of variations.

 

[seanieg89]

That said, most high school teachers wouldn't really know the difference, so its not a particularly important point.

 

[barbernator]

x-2 - 5 / x-2

Nightweaver has 4 instead of 5

its supposed to be a 4, do the division and you get -4 as the remainder

 

[umm what]

Bro its a question in fitzy
I did the division, i get 5 and so does the book
you get 1-6 at the end which = 5

its supposed to be a 4, do the division and you get -4 as the remainder

 

[nightweaver066]

Bro its a question in fitzy
I did the division, i get 5 and so does the book
you get 1-6 at the end which = 5

Wolframalpha tells me otherwise..

Link

Either me, wolframalpha and barbenator are wrong, the Fitzpatrick book is wrong, or you typed the question wrong.

 

[umm what]

x-3 - 5 / x-2 THAT IS THE CORRECT ANSWER

 

[AAEldar]

x-3 - 5 / x-2 THAT IS THE CORRECT ANSWER

It is.

In the quote that nightweaver has of you there is a 2 in the numerator, but you must have edited it just after he quoted and changed it to a 1.

I advise you to settle down though.

 

[nightweaver066]

It is.

In the quote that nightweaver has of you there is a 2 in the numerator, but you must have edited it just after he quoted and changed it to a 1.

I advise you to settle down though.

:S Did not realise the edit.. Should have double checked.

 

[Accuracy]

this is 4u question? isn't this somethin we learn in 2u as well? O_O . Is this the level of integration i'd expect if i continue to do 4u ??

 

[nightweaver066]

this is 4u question? isn't this somethin we learn in 2u as well? O_O . Is this the level of integration i'd expect if i continue to do 4u ??

No it's not a 4U question lol.

4U you could get something like..

 

[RealiseNothing]

No it's not a 4U question lol.

4U you could get something like..

Even then this is a relatively standard 4U integration question.

 

[deswa1]

Even then this is a relatively standard 4U integration question.

To be honest, you won't see something this hard in the HSC. I thought about how to do it initially, then I cheated and looked at the answer on wolfram- its obvious why there's no easy way : http://www.wolframalpha.com/input/?i=integrate+x%2F(1%2Bx^6)

 

[nightweaver066]

To be honest, you won't see something this hard in the HSC. I thought about how to do it initially, then I cheated and looked at the answer on BOS- its obvious why there's no easy way : http://www.wolframalpha.com/input/?i=integrate+x%2F(1%2Bx^6)

I must have remembered the question wrongly.. Or i can't think of the method..

Ahh. Factorise bottom, partial fractions. Gets quite messy.... Too long actually..

 

[umm what]

HSC WOULD BE REALLY EASY
I RECKON

To be honest, you won't see something this hard in the HSC. I thought about how to do it initially, then I cheated and looked at the answer on BOS- its obvious why there's no easy way : http://www.wolframalpha.com/input/?i=integrate+x%2F(1%2Bx^6)

 

[RealiseNothing]

To be honest, you won't see something this hard in the HSC. I thought about how to do it initially, then I cheated and looked at the answer on BOS- its obvious why there's no easy way : http://www.wolframalpha.com/input/?i=integrate+x%2F(1%2Bx^6)

lol I just looked at the question and assumed it was a simple substitution question.

 

[deswa1]

I must have remembered the question wrongly.. Or i can't think of the method..

Yeah, I think I know what you're talking about. I've seen questions very similar to that and I thought those methods would work but if what wolfram has is the simplest answer, we must have misremembered it.

 

[umm what]

how do youse get time time to do all these questions? LOL

Yeah, I think I know what you're talking about. I've seen questions very similar to that and I thought those methods would work but if what wolfram has is the simplest answer, we must have misremembered it.

 

[bleakarcher]

You can actually doing it using elementary methods. Just use the substitution u=x^2 then decompose the fraction.

 

[AAEldar]

View attachment 24980 Isn't this how you do it?

Noooo, you can't split the denominator up like that.

Also it'd be .

And you lots the half.