• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

mechanics plz help. (1 Viewer)

FinalFantasy

Active Member
Joined
Jun 25, 2004
Messages
1,179
Gender
Male
HSC
2005
yea dats a damn nice move...
i think i probably won't be able to come up with that during an exam:(

i better go now...

and plz.. no more saying things about me!!
i am really not as good as u think and i probably won't even get a 90 in mx2 since i stuffed da half yearlies pretty bad :( :mad:

ttyl!!
 

maths > english

Rejected Member
Joined
Feb 19, 2004
Messages
85
Gender
Undisclosed
HSC
2004
lol, theres no way youll get below 90 in mx2 final fantasy

u only need to beat 75% of 4u students to get 91 and there are alot of idiots doing 4u

people at my school last year couldnt even do the integration questions at the start of the 4u exam
 

who_loves_maths

I wanna be a nebula too!!
Joined
Jun 8, 2004
Messages
600
Location
somewhere amidst the nebulaic cloud of your heart
Gender
Male
HSC
2005
okay, ttyl FinalF.

and in case you might read this thread again some other time:

i had a thought about that question just then and it's pretty easy to work out even without the first part of the question that KFunk provided that leads you into doing the second part - in fact, you don't really need a "lead-in", it should automatically become part of your working out if you try to just do the integral on its own, this is what i just did:

Int[ln(1+tanx)dx] between {0, and pi/4):

using special properties of definite integrals - original integral = Int[ln(1+tan(pi/4 -x))dx] between {0, and pi/4} ;
now, tan(pi/4 -x) = (tan(pi/4) - tanx)/(1 + tan(pi/4)*tan(x)) = (1-tanx)/(1+tanx) = (cosx -sinx)/(cosx +sinx) ;
hence, Int[ln(1+tan(pi/4 -x))dx] = Int[ln(1 +(cosx -sinx)/(cosx +sinx))dx] = Int[2cosx/(cosx +sinx)dx] ;
now, the original integral: Int[ln(1+tanx)dx] = Int[ln((cosx+sinx)/cosx)dx] ;

hence, 2I = Int[2cosx/(cosx +sinx)dx] + Int[ln((cosx+sinx)/cosx)dx] = Int[ln(2) dx] between {0, and pi/4} ;
ie. 2I = ln(2)*(pi/4) -----> I = ln(2)*(pi/8)


see? the whole thing by itself without the need of a "lead-in" is not long at all :)
 

FinalFantasy

Active Member
Joined
Jun 25, 2004
Messages
1,179
Gender
Male
HSC
2005
int. f(x) from 0 to a=int. f(a-x) from 0 to a
that thing isn't supposed to be in the 4u syllabus, u gota derive it first i think
 

who_loves_maths

I wanna be a nebula too!!
Joined
Jun 8, 2004
Messages
600
Location
somewhere amidst the nebulaic cloud of your heart
Gender
Male
HSC
2005
Originally Posted by FinalFantasy
int. f(x) from 0 to a=int. f(a-x) from 0 to a
that thing isn't supposed to be in the 4u syllabus, u gota derive it first i think..
are you sure it's not part of the syllabus? cause every class in our school learnt it... it's part of the Patel and Excel books, and it was part of our exams once too.

plus, the derivation is quite simple, just let X=a-x , and go from there...
 

shafqat

Member
Joined
Aug 20, 2003
Messages
517
Gender
Undisclosed
HSC
N/A
It's in the syllabus, but you can't assume the result. They'll ask you to prove it before giving a question that uses the result.
 

haboozin

Do you uhh.. Yahoo?
Joined
Aug 3, 2004
Messages
708
Gender
Male
HSC
2005
FinalFantasy said:
int. f(x) from 0 to a=int. f(a-x) from 0 to a
that thing isn't supposed to be in the 4u syllabus, u gota derive it first i think

yea thats definatly in the syllabus there is a whole chapter on it aswell..

last chapter in integration in cambridge.
 

FinalFantasy

Active Member
Joined
Jun 25, 2004
Messages
1,179
Gender
Male
HSC
2005
yea i saw it in da cambridge book.. but i remember someone saying it's not in da syllabus.. o well i was wrong:p
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top