Maths question to solve (1 Viewer)

[2323]

Does anyone know how to solve

2^2x -6(2^x) + 8 = 0

 

[falsenthusiasm]

((2^x)^2) - 6(2^x) + 8 = 0

Let A = 2^x

Think you can do the rest?

 

[Sendoh08]

^ Yup whay he said:

((2^x)^2) - 6(2^x) + 8 = 0

A^2 - 6A + 8 = 0

(A - 4)(A - 2) = 0 (Factorising above line)

A = 4 or A = 2

2^x = 4 or 2^x = 2

therefore x=2 or x=1

And thats the working and solution =)

 

[Sy123]