They both work out to give the same z score, but if the question is clearly a sample proportion (says something like 'A random sample of 50 boxes from the 200 were tested' or something like that), then use the sample proportion method just in case.Y'all, just confirming, for binomial distribution questions, is it fine if you use either sample proportioning method or the count method to solve the q's, particularly to obtain z-scores?
Thanks
