~~Mathematics Revising Game~~ (1 Viewer)

[tulZzz]

why study for MATHS dont panic..it's fun and easy over studying and stressing wont get you anywhere

 

[old.skool.kid]

CD=2sin A
DE=2sin^2 A

soo
a=2sin A
r=sin A
limitin sun = 2sin A/(1-sin A)
i think thats it, not too hard

Doesnt it ask for just the first four though?

 

[Js^-1]

Here's one for the insomniacs...

Find the equation of the normal to the curve
y = x² + 2kx + (k+2)
at the origin.

Hence or otherwise find the equation of the normal to the curve
y = x² + 8x + 6
at the origin.

 

[Zeber]

Doesn't even pass through the origin mate.

 

[Js^-1]

Sorry, my bad...Never trust any maths done after 11pm. How about this:

Find the integral of:

ke^xe^kx

 

[kangms]

Doesnt it ask for just the first four though?

Nope, find ALL the sides, so yea, its limiting sum.Pretty weird huh. Yea, i got (2sinA)/(1-sinA).

 

[Azreil]

e^x*e^kx + c

Graph the solution of 4x=<15=<-9x on a number line.

 

[kangms]

x=<(-5/3). Is there two answers or one?? O well,, next question. From my trials, the teacher was a bitch: "We know that 2^10=1024, so that 2^10 can be represented by a 4 digit numeral. How many digits are there in 2^1000 when written as a numeral?"

 

[Js^-1]

300?

2¹⁰⁰⁰ = (2¹⁰)¹⁰⁰
= (1024)¹⁰⁰
=(1.024x10³)¹⁰⁰
=1.024x10³⁰⁰

 

[lyounamu]

x=<(-5/3). Is there two answers or one?? O well,, next question. From my trials, the teacher was a bitch: "We know that 2^10=1024, so that 2^10 can be represented by a 4 digit numeral. How many digits are there in 2^1000 when written as a numeral?"

302

log 10(10) = 1 = 2 digits
log 10(100) = 2 = 3 digits

log10 (2^1000) = 1000 log10(2) = 301.0229... = 302 digits

 

[kangms]

Yea..i think its 302. Check the Success One book. It was a past HSC question. Does anyone have the solution for the 07 HSC question 10??...that is a killer question.

 

[old.skool.kid]

Yeah that was hard aye. I suck at trying to visualise the displacemant curve and whats going on.
http://community.boredofstudies.org/showthread.php?t=157046.

 

[kangms]

Thanks for the link. Helped me alot. Still don't get how to do the last question. That's 5 marks gone for me. Still good, got 108/120=90%