ohhh so you keep doing it? until you get an exact value?Originally posted by JKDDragon
You have to use the sin formula for quadrant 4.
I.e - sin x = sin (360 - x)
So you get - sin 5p/3 = sin (360 - 300) = sin (p/3)
ohhh so you keep doing it? until you get an exact value?Originally posted by JKDDragon
You have to use the sin formula for quadrant 4.
I.e - sin x = sin (360 - x)
So you get - sin 5p/3 = sin (360 - 300) = sin (p/3)
Originally posted by JKDDragon
Sorry, I made a mistake which was solely my fault.
x must be the acute angle.
So for example you have 5p/3. The acute angle translates to p/3. (The acute angle here is defined as the angle from the angle you're working with to the axes). So if you have 190 degrees, the acute angle is 10. If it's 330 degrees, then it's 30. If it's 120 degrees, then it's 60.
So say you have sin (300). sin 300 = sin (360 - 60) = - sin 60.
Hope that cleared things up, sorry about my utterly retarded mistake.
yeah but remember when i asked previously which quadrant i should be dealing with if i had like 5Pi/3 and you said when it's sin you use the formulas in the 2nd quad.Originally posted by JKDDragon
No, x MUST be the acute angle.
For 5p/3 we have 300 degrees. The acute angle is 60, thus x = 60.
So we have sin (360 - x) = - sin x, with x = 60.
So thus we have sin (360 - 60) = sin 300 = - sin 60 = - 1/2.
EDIT: You're using sin (180 - ___) for some reason, which isn't right. We're talking about the 4th quadrant, that is sin (360 - x), not sin (180 - x) which is for the 2nd quadrant.
hmmmm... oops lol... maybe i read wrong ...Originally posted by JKDDragon
Easy.
Say you have sin 5p/3.
You use the sin one for quadrant 4.
Say you have tan 4p/3
You use the tan one for quadrant 3.
hmmmm confusing... lol... i fink im just gonna guess it ... anyways.... now more shit to study, continuous functions, limits, ahh fuck those theorems!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Originally posted by JKDDragon
Because you have the acute angle x which is 0 < x < 90. Therefore 270 < sin (360 - x) < 360, which is in quadrant 4. Apply similar logic to the other formulas.
1903? ... i'll do your software stuff, if you do pick itOriginally posted by JKDDragon
No problems, you can pay me back next semester by doing all my 1903 assignments.
Originally posted by Carlito
ive spent everyday this week on 1001, and havnt had time to touch any other subject yet.
so far, after studying 1001 and not studying 1002, i still understand more of 1002....
its just ... ugh.... HELP! im so screwed
So you can see how screwed I'am for 1901.Originally posted by Winston
Want to continue tutoring me Collin? ... cause i spent days at the library trying to study 1001 it's sooo hard!
lol i don't get MVT's!Originally posted by JKDDragon
So you can see how screwed I'am for 1901.
Just study the middle parts of the course, applying the mean value theorem etc. The beginning and end parts of the course are pretty easy.. but complex numbers may give you a bit of trouble since you didn't do 4 unit.
I don't think I'm good enough to tutor you, lol. I'm having enough trying to study for a pass in 1902.
Computer ln(1000000)/1n8?