im not even sure if my 2ii is correctOriginally posted by JUB JUB
use ur answers from 2ii...think...units squared and triangles....hmmmm
im not even sure if my 2ii is correctOriginally posted by JUB JUB
use ur answers from 2ii...think...units squared and triangles....hmmmm
can u do 2 iv? or tell me howOriginally posted by Saul
ahem
AP^2 = (a^2 + b^2 - 2 a.b)/4
CP^2 = (a^2 + b^2 +2 a.b)/4
if its a right triangle, a.b goes to zero, and AP^2= CP^2 = BP^2 (BP cause AP = BP) therefore all the vertices are equidistant from the midpoint of the hypotenuse.
yeh how do i do that? gimme something to start withOriginally posted by Saul
for 2) iv) just find the plane that goes through C perpendicular to 'l' and equate it with the plane p, and you'll get a line of solutions
Originally posted by Carlito
pls pls pls i need help
Can anyone help me with parts (b) and (c) of this question:
and parts (iii) and (iv) of this question:
i concurOriginally posted by Wyvern
particularly 2 iii) and 2 iv...........i mean WTF