Lost And Found (1 Viewer)

[Rorix]

the correct answer is
x= (2+tant)/(1-2tant)
after integration you should have had
arctanx = t + arctan2

probably
x=tan(t+ arctan2) is acceptable

 

[ftr10]

or x=tan(t+2)

coz tan (arctan 2) = 2

3/84 so far

 

[Rorix]

but tan(x+ arctany) is not the same as tan(x+y)

 

[johnamos123]

LOST: PARTICLE OF INFINITE SPEED. In an unfortunate mishap, the BoS released a particle which attained infinite speed after arctan 1/2 seconds. Warning: Take care when catching, the particle has infinite momentum and does not obey the laws of physics.

If found, please return to the Board of Studies.


FOUND: Proof that maths teachers don't understand physics.

To claim, please see disgruntled Mathematics Extension One students.

if this particle reached the speed of light then due to einsteins laws of special relativity the particles length would contract to zero and would therefore, be invisible and unable to find. In this case the particle has exceeded the speed of light as its velocity is infinity. using the same law the length of this particle is:

sqrt(1 - infinty)*original length

 

[Archman]

..who cares

 

[blackbunny]

wats arctan

 

[blackbunny]

where did arctan1/2 come from

 

[withoutaface]

wats arctan

Inverse tan

 

[blackbunny]

how do you do this question from start to finish. I just dont get it and also this infinite speed

 

[Rorix]

if this particle reached the speed of light then due to einsteins laws of special relativity the particles length would contract to zero and would therefore, be invisible and unable to find. In this case the particle has exceeded the speed of light as its velocity is infinity. using the same law the length of this particle is:

sqrt(1 - infinty)*original length

the particle is a dot point, it has no length to lose


archman i do because i spent 2-3min trying to work out what i did wrong

 

[Archman]

no, i did the same during exam. the comment was directed at the relativity thingo