Log...is evil (1 Viewer)

[misericordia]

can someone solve and explain how to differentiate 2x3In(x-2)??????
EDIT: that 3 is meant to be 'power of 3'...(that small thing)

 

[pLuvia]

Use product rule
d/dx(2x³ln(x-2))
=6x²ln(x-2)+2x³/(x-2)

 

[Forbidden.]

http://calc101.com/webMathematica/derivatives.jsp

(2*x^3)*In(x-2)
Let u = 2x^3 and v = In(x-2)
So du/dx = 6x^2 and dv/dx = 1/(x-2)
So d(2x^3ln(x-2))/dx = 6x^2*ln(x-2) + 2x^3/(x-2)

I tend to avoid substitution in 2U.

 

[misericordia]

oooomg you guys thank you so mucccccccchhhhhhh ...some people are just so good at maths...