Locus Q help :( (1 Viewer)

[Drewk]

http://snag.gy/O5syt.jpg
please provide steps dunno how to do

 

[Carrotsticks]

Use the perpendicular distance formula between the line and an arbitrary point P(x, y) and let it be equal to the given distance.

 

[Drewk]

Use the perpendicular distance formula between the line and an arbitrary point P(x, y) and let it be equal to the given distance.

Sorry dont quite understand what u mean could u plz expand further ??

 

[P.T.F.E]

20. |(ax+ by + c)/sqrt. a^2 + b^2 | - recall perpendicular distance formula. distance =1 therefore this always has to = 1.

|(12x-5y-1)/sqrt.169|=1

(12x - 5y - 1) / sqrt.169 = 1 or (12x - 5y - 1) / sqrt.169 = -1
12x - 5y - 1 = sqrt 169 or (12x - 5y - 1) = - sqrt 169
12x -5y - 14= 0 , 12x -5y + 12= 0 AS SQRT169 = 13


HOPE THAT HELPS