Jelly Beans (1 Viewer)

[Speed6]

program that calculates volume: http://tinyurl.com/m7b4yzr

I didn't put any error checking or anything like that because cbf so if you enter negatives or letters then it will crash


inb4peoplesayit'savirus

Yeah why does it say its malicious?

 

[Speed6]

program that calculates volume: http://tinyurl.com/m7b4yzr

I didn't put any error checking or anything like that because cbf so if you enter negatives or letters then it will crash


inb4peoplesayit'savirus

lols

 

[seventhroot]

lols

lel ROFL

this is the code:

not sure if srs

Yeah why does it say its malicious?

since it is an executable file; I think your computer automatically blocks it

 

[Queenroot]

square is a badass that's why

 

[seventhroot]

square is a badass that's why

 

[anomalousdecay]

Use Heisenberg's uncertainty principle and the Schrodinger equation to find out the probability of the jelly beans not being inside the box, and already in someone else's stomach

 

[braintic]

They mentioned these guessing competitions in a documentary I saw a couple of years ago. I can't remember the overall theme of the documentary.
They tried the strategy of having the last guess and simply averaging all the guesses others made before them.
The accuracy was surprising.

 

[Speed6]

Guys I divide the volume of the toolbox by the volume of 1 jellybean and I get a massive answer in the thousands, I even minus 10% due to air gaps its still in the thousands...

 

[FancyPenguin]

are you sure it's entirely filled up?

 

[FancyPenguin]

just guess a number and go with it

 

[braintic]

Guys I divide the volume of the toolbox by the volume of 1 jellybean and I get a massive answer in the thousands, I even minus 10% due to air gaps its still in the thousands...

Instead of playing with the dimensions of ONE jellybean, why don't you play with the dimensions of a packet?
Buy a packet, use the dimensions to calculate how many packets would fit in the box, then count the number of jellybeans in the packet.
That way, the air gap is not guesswork.

 

[Speed6]

Instead of playing with the dimensions of ONE jellybean, why don't you play with the dimensions of a packet?
Buy a packet, use the dimensions to calculate how many packets would fit in the box, then count the number of jellybeans in the packet.
That way, the air gap is not guesswork.

Lol oright

 

[Lithone]

Instead of playing with the dimensions of ONE jellybean, why don't you play with the dimensions of a packet?
Buy a packet, use the dimensions to calculate how many packets would fit in the box, then count the number of jellybeans in the packet.
That way, the air gap is not guesswork.

But then there's usually more air in the packets due to commercial cheapness (cough chip packets cough) so there'd be an overestimation of air

Therefore an underestimation of jellybeans

 

[Speed6]

Ok guys so there was 800 something jelly beans in the toolbox.

They said a number between 800-815 iirc.

 

[Rhinoz8142]

Wait guys if Adrita cant confirm, I cant go ahead with the calculation.

Whats the number of guesses

 

[Queenroot]

Wait guys if Adrita cant confirm, I cant go ahead with the calculation.

LMAO still can't believe you said this

 

[Squar3root]

program that calculates volume: http://tinyurl.com/m7b4yzr

I didn't put any error checking or anything like that because cbf so if you enter negatives or letters then it will crash

inb4peoplesayit'savirus

did anyone actually use my program?

 

[Speed6]

did anyone actually use my program?

Computer just wouldn't open it no matter what, my anti-virus program blocked it for good.

 

[Queenroot]

did anyone actually use my program?

I'll use it today sometime