IPT question help- HSC Q6 (2019 paper) (1 Viewer)

[queenb_3]

Hi guys,

Could someone help me with the following question please, and provide worked solutions (attached- it’s from the 2019 HSC paper Question 6)?

Thank you

 

[cossine]

The size is given in bytes.

Each variable size is given in bytes. So if take you the ASCII code you will see each character is 1 byte e.g. 0000000 contains 8 bits as there are 8 binary digits. This is equivalent to 1 byte as 8 bits = 1 byte.

Each record contains 10+ 8+ 5 + 4 Bytes.

There 512 records so the total number of Bytes is 512*(10+8+5+4).

We know 1024 bytes = 1 kB (kilobytes)


=> 1 btye = 1/(1024) kB

=> 512*(10+8+5+4) = 512*(10+8+5+4) / (1024) kB

So the answer is D

 

[queenb_3]

The size is given in bytes.

Each variable size is given in bytes. So if take you the ASCII code you will see each character is 1 byte e.g. 0000000 contains 8 bits as there are 8 binary digits. This is equivalent to 1 byte as 8 bits = 1 byte.

Each record contains 10+ 8+ 5 + 4 Bytes.

There 512 records so the total number of Bytes is 512*(10+8+5+4).

We know 1024 bytes = 1 kB (kilobytes)


=> 1 btye = 1/(1024) kB

=> 512*(10+8+5+4) = 512*(10+8+5+4) / (1024) kB

So the answer is D

Thank you so much!