Integration (1 Viewer)

[Lukybear]

y=2/(2x-6)

Find the volume of the solid of revolution by rotating the curves around the x axis, x=5, x=6.

Do not get the method of this question. Please help!

 

[gurmies]

 

[askJEEBS]

Replace (x-2) with (x-3) and you'll be fine.

 

[addikaye03]

y=2/(2x-6)

Find the volume of the solid of revolution by rotating the curves around the x axis, x=5, x=6.

Do not get the method of this question. Please help!

V=pi int. (y^2) dx where y= 2/2x-6 which =1/(x-3). Therefore y^2=1/(x-3)^2

V=|-pi1/[x-3]|from 5 to 6

pi(1/2-1/3)=pi/6 unit sq

 

[Lukybear]

O darn. Didnt know recognise the ability to simplify. How stupid.

But what if it was give 5/(2x-6)??

 

[annabackwards]

O darn. Didnt know recognise the ability to simplify. How stupid.

But what if it was give 5/(2x-6)??

The only thing would be the simplification.
You'd integrate ^2 = 25/4(x-3)^2
Which would equal 25pi/4x6 = 25pi/24

 

[Lukybear]

O thx so mcuh. Forgot about that identy. O man, im screwed for my tests upcoming.

 

[gurmies]

Replace (x-2) with (x-3) and you'll be fine.

Woops, how careless.