Integration Q!! (1 Viewer)

[sAppY..]

Heyy guyyz.

Help me to solve this question.

Find the area enclosed between the curves y =(x-1)^2 and y=5-x^2

 

[Steth0scope]

You need to find your x coordinates first. Do that by solving them as simulataneous equations. You should get x=2 and x= -1.

Now you perform and integration with the upper limit as x=2 and lower limit x= -1.
You are integrating the upper area minus the lower area so you put the upper graph before the lower graph in the integral (and minus the lower graph). i.e. you are integrating 5-x^2 - (x-1)^2.

Expand that and integrate it. Hope i didnt confuse u. Good luck.

 

[Steth0scope]

i did.

Its pretty hard to draw a sketch in a post lol

 

[sAppY..]

You need to find your x coordinates first. Do that by solving them as simulataneous equations. You should get x=2 and x= -1.

Now you perform and integration with the upper limit as x=2 and lower limit x= -1.
You are integrating the upper area minus the lower area so you put the upper graph before the lower graph in the integral (and minus the lower graph). i.e. you are integrating 5-x^2 - (x-1)^2.

Expand that and integrate it. Hope i didnt confuse u. Good luck.

Thank you! I got it. Totally not confused. gaga.

 

[Forbidden.]

i did.

Its pretty hard to draw a sketch in a post lol

Google "Graphmatica" without quotes.
Top curve is y = (x - 1)²
Bottom curve is y = 5 - x²

 

[Steth0scope]

That's pretty good. Thanks