If in a metal displacement reaction, nothing happens, can you write net ionic? (1 Viewer)

[Fiction]

If in a metal displacement reaction the metal is less reactive than the solution (and so nothing happens), can you write a net ionic equation?

Like full would be

AB(aq) + C(s) ---> AB(aq) + C(s)
OR
is it written as :
AB(aq) + C(s) ---> No reaction ?


full ionic
A+n(aq)B-n(aq) + C(s)---> A+n(aq)B-n(aq) + C(s)

but I can't figure out what the net ionic equation would be since there's no spectator thingies. Does it exist? As in can you write, "does not exist" or just repeat full ionic?

Also, how would you write the half equations of AB and C? Can I write both of them as reduction? Or do they not exist b/c for a reduction to occur, an oxidation must also occur simultaneously?

 

[HeroicPandas]

Good question

Suppose A is less reactive than B

I'd say, since A is less reactive than B, then a displacement reaction will not occur. No need for ionic equation because there isn't any!(?)

 

[Fiction]

Good question

Suppose A is less reactive than B

I'd say, since A is less reactive than B, then a displacement reaction will not occur. No need for ionic equation because there isn't any!(?)

Thank you! Repped c:

 

[Queenroot]

You would just say there is no spontaneous reaction occurring. Don't need equations, just explain why there isn't a reaction.

 

[someth1ng]

AB(aq) + C(s) ---> No Reaction

This one.