-
Finished your HSC? Check out our University Discussion, Non-School forums or help out next year's HSC students! -
YOU can help the next generation of students in the community! Share your trial papers and notes on our Notes & Resources page
HSC Physics Marathon 2013-2015 Archive (1 Viewer)
- Thread starter Magical Kebab
- Start date
- Status
anomalousdecay
Premium Member
- Joined
- Jan 26, 2013
- Messages
- 5,766
- Gender
- Male
- HSC
- 2013
re: HSC Physics Marathon Archive
But yeah post up another question.
I got something a bit different actually (2.8227 E 24) but not sure though as I could have made a mistake somewhere.
But yeah post up another question.
re: HSC Physics Marathon Archive
A basketball initially at rest is dropped from a height, collides with the ground and bounces back up. Assuming the collision is elastic, sketch graphs of acceleration over time, velocity over time for 2 bounces on different sets of axis.
A basketball initially at rest is dropped from a height, collides with the ground and bounces back up. Assuming the collision is elastic, sketch graphs of acceleration over time, velocity over time for 2 bounces on different sets of axis.
anomalousdecay
Premium Member
- Joined
- Jan 26, 2013
- Messages
- 5,766
- Gender
- Male
- HSC
- 2013
Re: HSC Physics Marathon Archive
This thread is an archive. Please post in the thread linked below for anything regarding a question in this thread:
http://community.boredofstudies.org/18/physics/331294/hsc-physics-marathon-2015-a.html
Make sure to quote what you are inquiring about!
This thread is an archive. Please post in the thread linked below for anything regarding a question in this thread:
http://community.boredofstudies.org/18/physics/331294/hsc-physics-marathon-2015-a.html
Make sure to quote what you are inquiring about!
Last edited:
Fizzy_Cyst
Owner @ Sigma Science + Phys Goat
re: HSC Physics Marathon Archive
Person A and Person B both fly to a planet which is 25 light years away.
Person B flies at 0.8c and Person B flies at 0.6c.
When both people arrive, who is older and by how much?
Person A and Person B both fly to a planet which is 25 light years away.
Person B flies at 0.8c and Person B flies at 0.6c.
When both people arrive, who is older and by how much?
Rhinoz8142
Well-Known Member
re: HSC Physics Marathon Archive
The one with the highest dilation is the oldest
Subtract with result of time dilation thus providing the difference
Is this right ?
Sorry , I am out right now... Don't have calculator
Find the time dilation
The one with the highest dilation is the oldest
Subtract with result of time dilation thus providing the difference
Is this right ?
Sorry , I am out right now... Don't have calculator
beaubrah
Member
- Joined
- Jan 25, 2014
- Messages
- 109
- Gender
- Male
- HSC
- 2015
re: HSC Physics Marathon Archive
They should have made it "What was the mass"
I guess that would trick a few people seeing as it is unaffected by the acceleration due to gravity
D
enjoi
rexona <3
They should have made it "What was the mass"
I guess that would trick a few people seeing as it is unaffected by the acceleration due to gravity
Fizzy_Cyst
Owner @ Sigma Science + Phys Goat
PhysicsMaths
Active Member
- Joined
- Dec 9, 2014
- Messages
- 179
- Gender
- Male
- HSC
- 2015
re: HSC Physics Marathon Archive
For person A, it would take 25/0.8 = 31.25 years
For person B, it would take 25/0.6 = 41.67 years
But time also dilates so...
using tv = t0 / √(1-v^2/c^2)
For A, 25√ (1-(0.8)^2 = 15 years
For B, 25√ (1-(0.6)^2 = 20 years
Difference = (41.67-31.25)-(20-15)
= 5.42 years -> Person B will be 5.42 years older than person A
Hmm.. not too sure, but:
For person A, it would take 25/0.8 = 31.25 years
For person B, it would take 25/0.6 = 41.67 years
But time also dilates so...
using tv = t0 / √(1-v^2/c^2)
For A, 25√ (1-(0.8)^2 = 15 years
For B, 25√ (1-(0.6)^2 = 20 years
Difference = (41.67-31.25)-(20-15)
= 5.42 years -> Person B will be 5.42 years older than person A
Fizzy_Cyst
Owner @ Sigma Science + Phys Goat
re: HSC Physics Marathon Archive
Right approach, finding both proper time and dilated time, but you have made a boo boo with the t0 when calculating dilated time
btw, strong first post!
According to what you have done, A should age ~27 years, but B only ages 20 years. The person who travels faster will always age less
Right approach, finding both proper time and dilated time, but you have made a boo boo with the t0 when calculating dilated time
btw, strong first post!
According to what you have done, A should age ~27 years, but B only ages 20 years. The person who travels faster will always age less
PhysicsMaths
Active Member
- Joined
- Dec 9, 2014
- Messages
- 179
- Gender
- Male
- HSC
- 2015
re: HSC Physics Marathon Archive
For person B, it would take 25/0.6 = 41.67 years
But time also dilates so...
using tv = t0 / √(1-v^2/c^2)
For A, 31.25√ (1-(0.8)^2 = 18.75 years
For B, 41.67√ (1-(0.6)^2 = 33 years
So B will be older, arriving (33-18.75)-(41.67-18.75) = 4.2 years after A
For person A, it would take 25/0.8 = 31.25 yearsRight approach, finding both proper time and dilated time, but you have made a boo boo with the t0 when calculating dilated time
btw, strong first post!
According to what you have done, A should age ~27 years, but B only ages 20 years. The person who travels faster will always age less
For person B, it would take 25/0.6 = 41.67 years
But time also dilates so...
using tv = t0 / √(1-v^2/c^2)
For A, 31.25√ (1-(0.8)^2 = 18.75 years
For B, 41.67√ (1-(0.6)^2 = 33 years
So B will be older, arriving (33-18.75)-(41.67-18.75) = 4.2 years after A
Fizzy_Cyst
Owner @ Sigma Science + Phys Goat
re: HSC Physics Marathon Archive
Question:
3 moons, X, Y and Z are in orbit around the same planet. The moons have identical orbital speeds, but masses of M, 9M and 25M respectively. Determine the ratio of their orbital radii and justify your answer.
Question:
3 moons, X, Y and Z are in orbit around the same planet. The moons have identical orbital speeds, but masses of M, 9M and 25M respectively. Determine the ratio of their orbital radii and justify your answer.
re: HSC Physics Marathon Archive
Find the ratio of the forces of gravity on the moons.
Fizzy_Cyst
Owner @ Sigma Science + Phys Goat
re: HSC Physics Marathon Archive
no, just another questionIs that your answer?
If so, nope
- Status