HSC exam chemistry solutions for the 2001 paper (1 Viewer)

[adomad]

Hey world. i wanted to know if anyone could tell me where the answers are to the HSC papers??/

i did question 23 from the paper and i want to know if i am correct or not

cheers,

ps, i got 83.333 grams.

i just found the answer in a success one book and the answer is 82.0 grams...

 

[no one]

...im assuming youve tried board of studies...
...anyways, i thought this site was pretty cool..
ARC :: Standards Packages
...its useful for all subjects...i think...ive only used ancient history..

 

[mitochondria]

I'm sure you already know how to do this so I'm not going to go into the calculation in details but only the bits that are important.

n_HCl = 0.1000 mol.L^-1 x 0.0244 L = 2.44 x 10^-3 mol


Assuming that the neutralisation has a 1:1 ratio for HCl:NaX (which is why this question was so poorly written...):

m_NaX = 10.0 g.L^-1 x 0.0200 L = 0.200 g


Molar mass of NaX is therefore:

M_NaX = m_NaX x n_HCl = 82.0 g.mol^-1


Hmmm... What did you do ?

 

[adomad]

I'm sure you already know how to do this so I'm not going to go into the calculation in details but only the bits that are important.

n_HCl = 0.1000 mol.L^-1 x 0.0244 L = 2.44 x 10^-3 mol


Assuming that the neutralisation has a 1:1 ratio for HCl:NaX (which is why this question was so poorly written...):

m_NaX = 10.0 g.L^-1 x 0.0200 L = 0.200 g


Molar mass of NaX is therefore:

M_NaX = m_NaX x n_HCl = 82.0 g.mol^-1


Hmmm... What did you do ?

AHAHA, yea i attempted the question already. i did it again and i realised that i got the volumes mixed up. thanks
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[pman]

Assume your wrong, not the book!