re: HSC Chemistry Marathon Archive
Moles of Ethanol = moles of H20 / 3
therefore 91/ Molar Mass of ethanol = 3*Volume H20 / 24.79
Volume = (91 * 3 * 24.79)/ 46.068
= 146.906........
= 150 (2 sig fig) L
I have a funny feeling I stuffed up somewhere because the units don't look right lewl
C2H50H (aq) + 302 (g) --> 2CO2 + 3H20Ethanol burns completely in oxygen producing carbon dioxide and water.
Calculate the volume of liquid water formed when the products are condensed at 25degC and 100kPa atmosphere if 91g of ethanol is used in the reaction
Moles of Ethanol = moles of H20 / 3
therefore 91/ Molar Mass of ethanol = 3*Volume H20 / 24.79
Volume = (91 * 3 * 24.79)/ 46.068
= 146.906........
= 150 (2 sig fig) L
I have a funny feeling I stuffed up somewhere because the units don't look right lewl
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