help: (1 Viewer)

umm what · Mar 18, 2012

need help with this question....

nightweaver066 · Mar 18, 2012

raufmalik said:
need help with this question....

$arg((1 + i)z)$

$arg(1 + i) + arg(z)$

$\frac{\pi}{4} + arg(z)$

$I'm sure you can do the rest yourself.$

umm what · Mar 18, 2012

nah can u do it for me? thnx

nightweaver066 said:
$arg((1 + i)z)$

$arg(1 + i) + arg(z)$

$\frac{\pi}{4} + arg(z)$

$I'm sure you can do the rest yourself.$

umm what · Mar 18, 2012

idk how to shade the region

raufmalik said:
nah can u do it for me? thnx

nightweaver066 · Mar 18, 2012

I won't draw the region for you, but i'll explain it to you.

$0 \leq \frac{\pi}{4} + arg(z) \leq \frac{\pi}{2}$

$-\frac{\pi}{4} \leq arg(z) \leq \frac{\pi}{4}$

The region is in between arg(z) = pi/4 and arg(z) = -pi/4

First draw these two rays emanating from the origin (with an open circle at the origin of course).

Label the angles (pi/4 for the upper ray and pi/4 for the lower ray) so the region you're sketching is clear.

The question asks for the region in between these two rays, so shade that region.

umm what · Mar 18, 2012

ok ok i get it ...thnx bro

nightweaver066 said:
I won't draw the region for you, but i'll explain it to you.

$0 \leq \frac{\pi}{4} + arg(z) \leq \frac{\pi}{2}$

$-\frac{\pi}{4} \leq arg(z) \leq \frac{\pi}{4}$

The region is in between arg(z) = pi/4 and arg(z) = -pi/4

First draw these two rays emanating from the origin (with an open circle at the origin of course).

Label the angles (pi/4 for the upper ray and pi/4 for the lower ray) so the region you're sketching is clear.

The question asks for the region in between these two rays, so shade that region.

Carrotsticks · Mar 18, 2012

asianese · Mar 18, 2012

^ omg totally does Zs like me!

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