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math man

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let u= sinx,



we now sub sinx for u and cosxdx for du as follows:



which im sure you can finish
 

D94

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u = sinx
du/dx = cosx
du = cosx dx
du = cosx dx

Substitute into the question to get: (u^2 * du)

Change the limits because you're integrating with respect to u now (du). Then apply a simple integration of u squared.
 
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math man

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you can also integrate it straight away realsing that cosx is the derivate of sinx using the reverse power rule for integrals:



which is in the cambridge 3u book..but this is more a 4u formula
 

D94

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The derivative of u=sinx is du/dx=cosx, NOT -cosx
Yeah, my bad. Fixed.

OP, You can use the reverse chain rule method if you know it (ie. integrate with respect to sinx)
 

barbernator

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you could draw accurate graphs on really small grid paper and count the number of squares underneath?
 

b3kh1t

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Yeah, my bad. Fixed.

OP, You can use the reverse chain rule method if you know it (ie. integrate with respect to sinx)
you can also integrate it straight away realsing that cosx is the derivate of sinx using the reverse power rule for integrals:



which is in the cambridge 3u book..but this is more a 4u formula
This is the general method for the students at the extension 2 level and it is usually not taught in 2 unit or extension 1 maths.
 

artosis

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Actually, i know this is acceptable in 4u, ive seen heaps of solutions do it
but in 3u, if it doesnt ask for substitution specifically, are we allowed to quote this formula and use it?
/will it guarantee those 3 or 4 marks?
 
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b3kh1t

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Actually, i know this is acceptance in 4u, ive seen heaps of solutions do it
but in 3u, if it doesnt ask for substitution specifically, are we allowed to quote this formula and use it?
/will it guarantee those 3 or 4 marks?
You should be allowed, however it is very rare for them to give you a question in 3 unit where you must find what you need to substitute. But if you do, then you must show your working out, so state the formula and I believe that you should receive the marks.
 

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