i still dont get itlet u = sinx, then you can do it by substitution easy
okay got it. thanks dude!!! the man!let u= sinx,
we now sub sinx for u and cosxdx for du as follows:
which im sure you can finish
The derivative of u=sinx is du/dx=cosx, NOT -cosxu = sinx
du/dx = -cosx
Yeah, my bad. Fixed.The derivative of u=sinx is du/dx=cosx, NOT -cosx
i hope this is a troll lolyou could draw accurate graphs on really small grid paper and count the number of squares underneath?
LOL, I actually thought this was funny. How accurate is your counting?you could draw accurate graphs on really small grid paper and count the number of squares underneath?
Yeah, my bad. Fixed.
OP, You can use the reverse chain rule method if you know it (ie. integrate with respect to sinx)
This is the general method for the students at the extension 2 level and it is usually not taught in 2 unit or extension 1 maths.you can also integrate it straight away realsing that cosx is the derivate of sinx using the reverse power rule for integrals:
which is in the cambridge 3u book..but this is more a 4u formula
i actually lol'dyou could draw accurate graphs on really small grid paper and count the number of squares underneath?
Actually, i know this is acceptable in 4u, ive seen heaps of solutions do it
You should be allowed, however it is very rare for them to give you a question in 3 unit where you must find what you need to substitute. But if you do, then you must show your working out, so state the formula and I believe that you should receive the marks.Actually, i know this is acceptance in 4u, ive seen heaps of solutions do it
but in 3u, if it doesnt ask for substitution specifically, are we allowed to quote this formula and use it?
/will it guarantee those 3 or 4 marks?