L lousinoa New Member Joined Dec 14, 2017 Messages 9 Gender Female HSC 2017 May 11, 2018 #1 In the question attached, I’m not sure how I’m meant to explain the geometric relationship. Any help would be greatly appreciated Attachments C7117107-BF4B-4498-B5BD-1C1AC36B7D5D.jpeg 47.4 KB Views: 32 899F057A-4F3D-4D26-861B-D3852A0E540F.jpeg 27.4 KB Views: 24
In the question attached, I’m not sure how I’m meant to explain the geometric relationship. Any help would be greatly appreciated
BenHowe Active Member Joined Aug 20, 2015 Messages 354 Gender Male HSC 2016 Uni Grad 2020 May 12, 2018 #2 isnt just your cubing the function output each time. Like for some point a, you get f(a) for y=x^1/3 then cube it to get y=x, then cube it again to y=x^3
isnt just your cubing the function output each time. Like for some point a, you get f(a) for y=x^1/3 then cube it to get y=x, then cube it again to y=x^3
T Ted_ New Member Joined Jun 3, 2017 Messages 8 Location Greenacre Gender Male HSC 2018 May 12, 2018 #3 It could also be that they y=x is the mirror, and y=x^1/3 is the inverse of y=x^3. But idk about that. The questions seems a bit too vague.
It could also be that they y=x is the mirror, and y=x^1/3 is the inverse of y=x^3. But idk about that. The questions seems a bit too vague.
