Help with geometric relationship (1 Viewer)

[lousinoa]

In the question attached, I’m not sure how I’m meant to explain the geometric relationship. Any help would be greatly appreciated

 

[BenHowe]

isnt just your cubing the function output each time. Like for some point a, you get f(a) for y=x^1/3 then cube it to get y=x, then cube it again to y=x^3

 

[Ted_]

It could also be that they y=x is the mirror, and y=x^1/3 is the inverse of y=x^3. But idk about that. The questions seems a bit too vague.