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help with a physics question (1 Viewer)

s_bilgrami89

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A force of 16n acts for 3.6 sec on an object of mass 8.35kg with an initial velocity of 30m/s. If the force acts in the same direction as the initial velocity, what would the objects new velocity be?
 

s_bilgrami89

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Two skaters, one of mass 60kg and the other 95kg stand together at rest on the ice rink. The first person (60kg) pushes himself away from the other so that he is travelling at 5m/s. Find the velocity of the second person after the push.
 
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khorne

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A force of 16n acts for 3.6 sec on an object of mass 8.35kg with an initial velocity of 30m/s. If the force acts in the same direction as the initial velocity, what would the objects new velocity be?
f = ma, a = v-u/t
 

_deloso

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A force of 16n acts for 3.6 sec on an object of mass 8.35kg with an initial velocity of 30m/s. If the force acts in the same direction as the initial velocity, what would the objects new velocity be?
f=ma -> a=f/m
a=16/8.35
=1.916

now acceleration = (velocity final - velocity initial)/change in time
therefore find velocity final by subbing values in
1.916 = (Vel final - 30)/3.6
Vel final - 30 = 1.916 x 3.6
Vel final = 6.8976 + 30
Vel final = 36.8976 m/s

is that the given answer?
 
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Two skaters, one of mass 60kg and the other 95kg stand together at rest on the ice rink. The first person (60kg) pushes himself away from the other so that he is travelling at 5m/s. Find the velocity of the second person after the push.
conservation of momentum

60 x 5 = 95 x V

solve for V
 

_deloso

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Two skaters, one of mass 60kg and the other 95kg stand together at rest on the ice rink. The first person (60kg) pushes himself away from the other so that he is travelling at 5m/s. Find the velocity of the second person after the push.
use momentum.
mv(skater 1) = mv(skater 2)
60 x 5 = 95 x v
300=95v
v=300/95
=3.16 m/s
 

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