HELP! Please - Trig Equation (1 Viewer)

[laura_hill]

My assesment is due in a couple of days and i have tried this using the t method, auxilary angle and a method our teacher showed me and i still can't find the 'exact' solution.

Find the exact solution for sin4t + √3cos4t = 0 for t (0≤t≤π)

Please Help.
I wil be eternaly grateful

 

[ninetypercent]

equating coefficients










where n is an integer
4t = (pi x n) - pi/3
t = pi/4 x n - pi/12

t = pi/6, 5pi/12, 2pi/3, 11pi/12

 

[Cazic]

Just another way /shrug.

 

[laura_hill]

Why is r = sqrt of 2?

I found r to be 2 using pythagoras and 1 and root 3

 

[addikaye03]

Why is r = sqrt of 2?

I found r to be 2 using pythagoras and 1 and root 3

r=2, 90% just made a small error. Cazic's solution is spot on. Usually a 3U question and would use the transformation method though. Usually lead into it with a) and b) style scaffold

 

[laura_hill]

Is there another way besides Cazic's method because i just don't seem to get it?

 

[gurmies]

Divide the equation by

 

[xV1P3R]

 

[Drongoski]

cazic's is the way to go.