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Help on intergration (1 Viewer)

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note the actual area you are rotating about the y axis, the volume is actually a cylinder of height 2 and radius 8 but from this cylinder you then subtract the volume of the curve about the y axis ( between y=0 and y=2 )

Volume of cylinder = pi r^2 h

so Volume = pi ( 8^2 ) (2 ) - pi integral (x^2) dy [ integrated from y=0..y=2 ]

now x^(1/3) =y
so x= y^3
x^2 = y^6

so volume = 128 pi - pi integral (y^6) dy [ from y=0..y=2]

you do calculations
thats the only kinda hard one that u wanna look at
 

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