help = integration problem! (1 Viewer)

[asb_92]

lol im confused... :S

umm its 1/(3-x)^2

are u guys using that formula:

integral of (ax+b)^n = [(ax+b)^n+1]/(n+1)a

??
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[Drongoski]

lol im confused... :S

umm its 1/(3-x)^2

are u guys using that formula:

integral of (ax+b)^n = [(ax+b)^n+1]/(n+1)a

??
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Don't u have the correct answer?

lychnobity's early answer was correct.

 

[Fortify]

Hang on a minute... isn't it 1/(3 - x) + C ??

This is the correct answer.

 

[asb_92]

nup i havnt got the correct answer but its liek a follow on question...

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[Drongoski]

lol im confused... :S

umm its 1/(3-x)^2

are u guys using that formula:

integral of (ax+b)^n = [(ax+b)^n+1]/(n+1)a

??
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most people do

 

[asb_92]

ok sweet

then i get lychnobity's too

thanks heaps guys
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[H4rdc0r3]

lol maths noobs.