• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Graph help (1 Viewer)

darkphoenix

Member
Joined
Mar 2, 2011
Messages
60
Gender
Male
HSC
2012
Can anyone show me how to graph y=(2x^3)/(x^2-4) , i got 3 turning points 0, +- root 12, but the answer is +-2.16. Ty
 

tywebb

dangerman
Joined
Dec 7, 2003
Messages
2,212
Gender
Undisclosed
HSC
N/A




So I think you are right. Where did you get this question from? It seems that "the answer" you have been provided with is incorrect.
 
Last edited:

darkphoenix

Member
Joined
Mar 2, 2011
Messages
60
Gender
Male
HSC
2012
math in focus , EX 2.8 Q 13 , I thought my answer is right until i used a graphing calculator and had the same answer as the textbook.
 

tywebb

dangerman
Joined
Dec 7, 2003
Messages
2,212
Gender
Undisclosed
HSC
N/A
i got 3 turning points 0, +- root 12
Note that (0,0) is not actually a turning point. It's a horizontal point of inflection.

Turning points are local extrema, not horizontal inflections.

Stationary points can be local extrema OR horizontal points of inflection.
 

darkphoenix

Member
Joined
Mar 2, 2011
Messages
60
Gender
Male
HSC
2012
O right, thanks, do you follow any steps when graphing: like limit to the asymptotes, even or odd, dividing regions etc. I get really confused when graphing these stuff?
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top