MedVision ad

General Thoughts: Physics (2 Viewers)

cyradis

New Member
Joined
May 19, 2012
Messages
10
Gender
Female
HSC
2013
Oh no! I mixed up photocell with solar cell asjhjfkhdakjf failllll
does anyone know how many marks i could get? :(
 
Last edited:

studybuddy101

Active Member
Joined
Apr 18, 2012
Messages
103
Gender
Male
HSC
2013
It's 51.91 to two dp. Use centripetal acceleration and set it to 1g (9.8). Radius is 550/2
 

iBibah

Well-Known Member
Joined
Jun 13, 2012
Messages
1,374
Gender
Male
HSC
2013
Q2Q was simple.
Interesting that all the big core questions came from Ideas.
Not very many hard qs, a couple of tricky MC though
My answers in Q2Q were quite mediocre, never really mastered it (though i do think i pumped the de Broglie question)
 

yasminee96

Active Member
Joined
Sep 8, 2012
Messages
346
Gender
Female
HSC
2013
There were many questions that required manipulation of topics. The long responses were good, but many students in the state, if not majority, would not have gotten the torque question with the weight on the end of the motor, or the centripetal force question (part a and b), and there were many tricks in the m/c. The emf graph would've put a lot of people off as well, any guarantee the long responses will be marked harsh (as per usual). It's super easy to make silly mistakes with almost half the paper being calculations.

Doubt the cut off will be any higher than last year. It may have been easier for most people on this site, but it was definitely different for others. Cut off will either be same or lower IMO
 

superSAIyan2

Member
Joined
Apr 18, 2012
Messages
320
Gender
Male
HSC
2013
I got 51.91 but not sure why g is 9.8. Is the space station being tested on earth
 

pls

New Member
Joined
May 27, 2013
Messages
8
Gender
Male
HSC
2013
I got rotational velocity = 73.4m/s. I equated f=ma with f=mv^2/r. You get v = √ (ar). Sub in a as 9.8 and r as the radius as 550.
 

panda15

Alligator Navigator
Joined
Feb 22, 2012
Messages
675
Gender
Male
HSC
2013
I got rotational velocity = 73.4m/s. I equated f=ma with f=mv^2/r. You get v = √ (ar). Sub in a as 9.8 and r as the radius as 550.
Diameter is 550, r is 275. Bored of Studies are just being pricks.
 

pls

New Member
Joined
May 27, 2013
Messages
8
Gender
Male
HSC
2013
+1 to the silly error count. What about the motor with the mass attached. Im not sure i got that. Did you say f=w=mg which is 0.49 N or something like that? Then for the next bit find torque using t=fd (with f from the previous question and d= radius of the shaft or whatever that was) and equate that with t=nbIAcosø to find current?
 

panda15

Alligator Navigator
Joined
Feb 22, 2012
Messages
675
Gender
Male
HSC
2013
+1 to the silly error count. What about the motor with the mass attached. Im not sure i got that. Did you say f=w=mg which is 0.49 N or something like that? Then for the next bit find torque using t=fd (with f from the previous question and d= radius of the shaft or whatever that was) and equate that with t=nbIAcosø to find current?
Yeah, I got about 0.163 I think.
 

studybuddy101

Active Member
Joined
Apr 18, 2012
Messages
103
Gender
Male
HSC
2013
+1 to the silly error count. What about the motor with the mass attached. Im not sure i got that. Did you say f=w=mg which is 0.49 N or something like that? Then for the next bit find torque using t=fd (with f from the previous question and d= radius of the shaft or whatever that was) and equate that with t=nbIAcosø to find current?
Yeah that's what I did. From memory 0.16 amps
 

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top