i made a stupid stupid transcription error in 6a(ii).. which gave me a wrong answer of 90m. far out, u reckon if the markers just see where i copied it to the next line wrong, will penalise me 1 mark, and give me 2/3.. or would i get 1?
wouldn't substitution of u=sinx be sufficient?tacogym27101990 said:i think the integration of sin2xcosx was abit harsh for the people that dont do 4 unit
but im not complaining =]
Yep.danz90 said:wouldn't substitution of u=sinx be sufficient?
yeah but in 3 unit exams they give you the substitutiondanz90 said:wouldn't substitution of u=sinx be sufficient?
ohkk i see were u coming from loltacogym27101990 said:yeah but in 3 unit exams they give you the substitution
so lots of peoplewouldntve known how
something along the lines of (sqrt2)/12danz90 said:ohkk i see were u coming from lol
well i instantly thought that by using u=sinx, u would eliminate the cosx with du/dx.
wat did u get as answer to this one btw?
i forgot wat i wrote
shit.ahhliss said:OH NO! I just wrote how long it would take, not the time it would be done!
even worsee...dwarven said:shit.
same here
>_<"
and it even said
what time [to the nearest min.] will it be cooked
That's exactly what i did!ahhliss said:OH NO! I just wrote how long it would take, not the time it would be done!
woot i got the sameetacogym27101990 said:something along the lines of (sqrt2)/12
thats what i did, but sometimes i worry its not enough workingu-borat said:how comez none of you know the leet method of integrating cosxsin^2x?
you integrate it straight to sin^3x /3
one step done.
You're making me nervous, I think I got something like that. What was the real answer?danz90 said:i made a stupid stupid transcription error in 6a(ii).. which gave me a wrong answer of 90m. far out, u reckon if the markers just see where i copied it to the next line wrong, will penalise me 1 mark, and give me 2/3.. or would i get 1?
answer was 96, u probably got it right.glockenspiel said:You're making me nervous, I think I got something like that. What was the real answer?
I found it ok, I answered everything.