factorising (1 Viewer)

WEMG · Feb 4, 2010

factorise:
a^4+a^2b^2+b^4

cutemouse · Feb 4, 2010

WEMG said:
factorise:
a^4+a^2b^2+b^4

$a^4+a^2b^2+b^4 = (a^2+b^2)^2$

spammy679 · Feb 4, 2010

jm01 said:
$a^4+a^2b^2+b^4 = (a^2+b^2)^2$

??

$(a^2 + b^2)^2 = a^4 + 2a^2b^2 + b4$

ilikebeeef · Feb 4, 2010

spammy679 said:
??

$(a^2 + b^2)^2 = a^4 + 2a^2b^2 + b4$

Lol agreed.

OP, are you sure you've typed the question correctly?

WEMG · Feb 4, 2010

the answer is different: (a^2+ab+b^2)(a^2-ab+b^2)
I don't know how factorise any equation like these with more than 3 different number in each bracket, the textbook(cambridge 3u) doesnt show how to do these ones.
I have typed it correctly btw

ninetypercent · Feb 4, 2010

$a^4+a^2b^2+b^4$

$(a^2 + b^2)^2 - a^2b^2$
then using difference of two squares, we get:

$= (a^2 + ab + b^2) (a^2 - ab + b^2)$

mmo · Feb 4, 2010

yeah first complete the square
the use the difference of 2 squares just like the above answer

WEMG · Feb 4, 2010

thanks

gurmies · Feb 4, 2010

jm01 said:
$a^4+a^2b^2+b^4 = (a^2+b^2)^2$

Lol, I've done that before too.

cutemouse · Feb 5, 2010

lol yeah I should RTQ properly

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