Factorial question (1 Viewer)
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yanujw
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Suppose you have n! that you want to express as the product of smaller factorials. Let the largest of these smaller factorials be k! e.g. in the above example n = 10 and k=7
n!/k! = n(n-1)(n-2)...(n-k+1)
For the example given, 10!/7! = 10 x 9 x 8 = 720
Then it is a matter of finding smaller factorial results that multiply to give this product. To make it easier, I reccomend trying values of k that are close to n at first.
1 set of solutions for this problem includes;
a) 7! x 6!
b) 2! x 4! x 47!
c) 4! x 23!
n!/k! = n(n-1)(n-2)...(n-k+1)
For the example given, 10!/7! = 10 x 9 x 8 = 720
Then it is a matter of finding smaller factorial results that multiply to give this product. To make it easier, I reccomend trying values of k that are close to n at first.
1 set of solutions for this problem includes;
a) 7! x 6!
b) 2! x 4! x 47!
c) 4! x 23!