L luo_ge Member Joined Sep 26, 2016 Messages 60 Gender Male HSC 2016 Feb 25, 2017 #1 I was just wondering on how to do these questions, there are no worked examples in my textbook. Any help would be greatly appreciated.
I was just wondering on how to do these questions, there are no worked examples in my textbook. Any help would be greatly appreciated.
I InteGrand Well-Known Member Joined Dec 11, 2014 Messages 6,109 Gender Male HSC N/A Feb 25, 2017 #2 luo_ge said: I was just wondering on how to do these questions, there are no worked examples in my textbook. Any help would be greatly appreciated. View attachment 33813 View attachment 33814 Click to expand... Use the reverse chain rule or substitution (let u equal the quadratic that appears).
luo_ge said: I was just wondering on how to do these questions, there are no worked examples in my textbook. Any help would be greatly appreciated. View attachment 33813 View attachment 33814 Click to expand... Use the reverse chain rule or substitution (let u equal the quadratic that appears).
pikachu975 Premium Member Joined May 31, 2015 Messages 2,739 Location NSW Gender Male HSC 2017 Feb 25, 2017 #3 luo_ge said: I was just wondering on how to do these questions, there are no worked examples in my textbook. Any help would be greatly appreciated. View attachment 33813 View attachment 33814 Click to expand... First one: Integrate x/(x^2 -1)^2 let u = x^2 - 1 du = 2xdx dx = du/2x => 1/2(u^2) Should be easy to integrate this and sub back in Second one: u=x^2 + 1 du = 2xdx dx = du/2x Should be easy to integrate from there and sub back in
luo_ge said: I was just wondering on how to do these questions, there are no worked examples in my textbook. Any help would be greatly appreciated. View attachment 33813 View attachment 33814 Click to expand... First one: Integrate x/(x^2 -1)^2 let u = x^2 - 1 du = 2xdx dx = du/2x => 1/2(u^2) Should be easy to integrate this and sub back in Second one: u=x^2 + 1 du = 2xdx dx = du/2x Should be easy to integrate from there and sub back in