Division of vectors?? (1 Viewer)

haboozin

Do you uhh.. Yahoo?
Joined
Aug 3, 2004
Messages
708
Gender
Male
HSC
2005
Hey, i forgot this and now im stuck... too much holidays have made me forget everything....



eg here is a question:

Describe the locus of the complex number w, where z is restricted as indicated:

w = (z - 2i)/(1 - z), |z| = 2

Can someone please write full steps in gaining the answer (preferably using algebra) but more than one method is good too :D
 

Captain pi

Member
Joined
Dec 3, 2004
Messages
433
Location
Port Macquarie
Gender
Male
HSC
2005
Answer

Here is the answer, as I believe:

w = (z – 2i)/(1 – z)

w(1 – z) = (z – 2i) [z =/= 1]

w – wz – z + 2i = 0

z(w + 1) = w + 2i

|z||w + 1| = |w + 2i|
(property of products: moduli equal)

2|w + 1| = |w + 2i| (by given |z| = 2)

4|w + 1|² = |w + 2i|²
let w = x + iy​

4((x + 1)² + y²) = x² + (y + 2)²

4(x² + 2x + 1 + y²) = x² + y² + 4y + 4

3x² + 8x + 3y² + 4y = 0

x² + (8/3)x + 16/9 + y² + (4/3)y + 4/9 = 20/9

(x + 4/3)² + (y + 2/3)² = 20/9

This is a circle with centre (–4/3 , –2/3) and radius (2/3)sqrt[5].

I hope that helped.

And so, Captain pi flew off, his task complete. But what will tomorrow bring? Calculus? Number Theory? The Ostrowski-Hadamard Gap Theorem? Only mathematics can tell.
 

haboozin

Do you uhh.. Yahoo?
Joined
Aug 3, 2004
Messages
708
Gender
Male
HSC
2005
captain pi your are so close,
the correct answer is
locus of w os a circle, radious 2/3(SQRT)5, Center (-4/3,2/3)


this is your mistake:
Captain pi said:
3x² + 8x + 3y² + 4y = 0
it should be:
3x² + 8x + 3y² - 4y = 0


well done though, thanks for the explination.


Captain pi said:
And so, Captain pi flew off, his task complete. But what will tomorrow bring? Calculus? Number Theory? The Ostrowski-Hadamard Gap Theorem? Only mathematics can tell.
Wow... that is... so..... nerdy.... I think that reaches new heights of nerdyness. You should write it on your hsc paper ;) HAHAHAHA.
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top