lukebennett
Happy Member
ok i have the answer.
CuSO4 conc=0.050 mol L-1
250mL thus to find the number of moles, 0.050x0.25L=0.0125 moles CuSO4
thus 0.0125 moles Cu2+ initially
then 0.325g are removed from solution =0.0051 moles Cu
thus number of moles finally= 0.0125-0.0051=0.0074 moles
c=n/v=0.0074/0.25=0.0296mol L-1
this is the answer i actually got in the exam. i originally only recalled the no moles i had found.so i think 0.03 would be ok
CuSO4 conc=0.050 mol L-1
250mL thus to find the number of moles, 0.050x0.25L=0.0125 moles CuSO4
thus 0.0125 moles Cu2+ initially
then 0.325g are removed from solution =0.0051 moles Cu
thus number of moles finally= 0.0125-0.0051=0.0074 moles
c=n/v=0.0074/0.25=0.0296mol L-1
this is the answer i actually got in the exam. i originally only recalled the no moles i had found.so i think 0.03 would be ok