Complex (2 Viewers)

[fullonoob]

I know this sound so simple, but I've never had to find the roots (apart for square) for something in cartesian form. I've always done it either just as a real number of just as an imaginary number.

Find the five-fifth roots of

and I'm tryna finish all my complex work tonight and I've got like 5 questions out of 153 I can't do

Hmm thats the exact same question i had in my exam O_O

 

[ninetypercent]

^ and did you get it right fullonoob?

 

[adomad]

 

[cyl123]

I assume the denominator is 1-ik

Let ABC be the triangle with A,B,C being complex numbers u,v and that fraction (sorry cbf typing it)
To show that it is right angled, try showing vector AC=ki*(vector BC)
ie. try u-(the fraction) and v-(the fraction), simplify and see what you get