Its wrong, but close. Check the moduli of the vectors, they don’t add up correctly, z1 to z2 is 5 but multiplying by Cis/4 only rotates it, it’s new moduli is also 5, which is incorrect, it should be shorter. I have the correct working out but can’t type it up until I get home, I’ll post again if I remember, the answer should be divided by sqrt2Eek I haven't done 4U in a while so I might be a bit rusty but this is what I got - hopefully it's right.
https://i.imgur.com/a8xeaNY.jpg
Essentially, since it's an isosceles triangle with z3 as a right angle, the remaining angles would be 45 degrees. Therefore, I think you can just manipulate the vector z1 and z2 by multiplying it with cis(pi/4) or cis (-pi/4) to eventually find z3.
Hopefully the working out in the image makes sense.
If I'm wrong let me know - I haven't done this in a while so I might've forgot some stuff.
Also, I believe you can have two values of z3 I think - one above the real axis and one below the real axis. I'm not fully sure though.
Ah yep that's true - silly mistake from me haha haven't done 4U in a while rip xD.Its wrong, but close. Check the moduli of the vectors, they don’t add up correctly, z1 to z2 is 5 but multiplying by Cis/4 only rotates it, it’s new moduli is also 5, which is incorrect, it should be shorter. I have the correct working out but can’t type it up until I get home, I’ll post again if I remember, the answer should be divided by sqrt2