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Complex Number Questions (1 Viewer)

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Forbidden. said:
Why the hell does the Board Of Studies use the 'cis' notation and what is it ?
its just a quicker way to write cos@ + isin@
which is just the modulus/arguement form of a complex number
 

ronnknee

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Forbidden. said:
Why the hell does the Board Of Studies use the 'cis' notation and what is it ?
cis @ is the notation for cos @ + isin @
It saves time and space writing it I guess xD
 
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Forbidden.

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tacogym27101990 said:
its just a quicker way to write cos@ + isin@
which is just the modulus/arguement form of a complex number
cis θ = cosθ + i sin θ ?
Nah, sometimes I just prefer e or the long way cosθ + i sin θ,
cis θ looks to confusing and impractical to me anyway.

and LOl at your sig ... sometimes fat physics textbook make bedtime story too.
 

Undermyskin

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I always write cis but I'm not sure if I can do it in the HSC exam. (?)
 

conics2008

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ohh that lol.. hehe i thoguht u meant this cos2x lol this is 3unit xD

this is what i thought

sina+sinb= 2sin(a+b/2)cos(a-b/2)

because they used it in the cambridge book to prove the gradient of a line in an ellipes...

ahhaha.. sorry im gettin too old for this shit.
 

conics2008

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ohh that lol.. hehe i thoguht u meant this cos2x lol this is 3unit xD

this is what i thought

sina+sinb= 2sin(a+b/2)cos(a-b/2)

because they used it in the cambridge book to prove the gradient of a line in an ellipes...

ahhaha.. sorry im gettin too old for this shit.
 

conics2008

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I use that form cis theta

c= cos theta
i = i
s= sin theta

theta=theta
 

conics2008

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there are these half angels

sin(x) = 2sinx/2cosx/2
cos(x) = cos^2(x/2)-sin^2(x/2)
= 2cos^2(x/2) -1

tan(x) = 2tanx/2 / 1 - tan^2 x/2

these im postive and the other i posted is not in the syllabus
 
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yeah they are
its just a different form of the cos2x and stuff
u just let sinx=sin(x/2+x/2)
then use the result we know of sin(A+B)=sinAcosB+cosAsinB
to get 2sinx/2cosx/2
and cos(A+B) is cosAcosB-sinAsinB
and i cant be bothered doin the tan one
 

conics2008

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tacogym27101990 said:
yeah they are
its just a different form of the cos2x and stuff
u just let sinx=sin(x/2+x/2)
then use the result we know of sin(A+B)=sinAcosB+cosAsinB
to get 2sinx/2cosx/2
and cos(A+B) is cosAcosB-sinAsinB
and i cant be bothered doin the tan one

Cool thanks =) HSC question aren't that hard except for 7 and 8 ... im confident i can get 1st 2nd 3rd and 4th.. full marks... unless i make stupid mistakes along the way.
 

ronnknee

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conics2008 said:
Cool thanks =) HSC question aren't that hard except for 7 and 8 ... im confident i can get 1st 2nd 3rd and 4th.. full marks... unless i make stupid mistakes along the way.
It's so relevant :|
 

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