http://prntscr.com/ejajz8 Q1 of Ekman's questions, is there both an algebraic and graphic way?
pikachu975 Premium Member Joined May 31, 2015 Messages 2,739 Location NSW Gender Male HSC 2017 Mar 13, 2017 #1 http://prntscr.com/ejajz8 Q1 of Ekman's questions, is there both an algebraic and graphic way?
pikachu975 Premium Member Joined May 31, 2015 Messages 2,739 Location NSW Gender Male HSC 2017 Mar 13, 2017 #2 pikachu975 said: http://prntscr.com/ejajz8 Q1 of Ekman's questions, is there both an algebraic and graphic way? Click to expand... http://prntscr.com/ejaqub Also how do you do part iii?
pikachu975 said: http://prntscr.com/ejajz8 Q1 of Ekman's questions, is there both an algebraic and graphic way? Click to expand... http://prntscr.com/ejaqub Also how do you do part iii?
S si2136 Well-Known Member Joined Jul 19, 2014 Messages 1,370 Gender Undisclosed HSC N/A Mar 13, 2017 #3 Yes, there is an algebraic and graphic way. For part 3, Product of Roots.
pikachu975 Premium Member Joined May 31, 2015 Messages 2,739 Location NSW Gender Male HSC 2017 Mar 13, 2017 #4 si2136 said: Yes, there is an algebraic and graphic way. For part 3, Product of Roots. Click to expand... What roots? Also what are the methods?
si2136 said: Yes, there is an algebraic and graphic way. For part 3, Product of Roots. Click to expand... What roots? Also what are the methods?
ishan New Member Joined May 14, 2016 Messages 25 Gender Male HSC 2017 Mar 13, 2017 #5 Yeah graphically works. draw a quadrilateral of Z,W and Z-W and Z+W. And you says its a rhombus cos its a parallrlogram with adjacent sides equal because mod Z=modW. Therefore the diagonals are prependicular Sent from my A1601 using Tapatalk
Yeah graphically works. draw a quadrilateral of Z,W and Z-W and Z+W. And you says its a rhombus cos its a parallrlogram with adjacent sides equal because mod Z=modW. Therefore the diagonals are prependicular Sent from my A1601 using Tapatalk