Chemistry Help - Calculations (1 Viewer)

[Andy005]

https://drive.google.com/open?id=0B_RlXPQTW1cRS0doZjlOQ0E0d0U

How do I attempt question b?

Any help would be greatly appreciated.

Thanks.

 

[Sp3ctre]

I can barely see the question but I think it's asking for the volume of oxygen.

The first step for any type of these questions is to write out a balanced chemical eq'n: 2Mg + O2 --> 2MgO

m(O2) = 32.95 - 32.63 = 0.32
n(O2) = 0.32/16*2

Then just use the eq'n: no. of moles = volume/molar volume
i.e. volume = (0.32/16*2) * 24.79 = 0.2479 L (to the nearest litre)

 

[Andy005]

Thanks