• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

can someone explain this working out for finding distance travelled. (1 Viewer)

ymcaec

Member
Joined
Apr 25, 2012
Messages
77
Gender
Undisclosed
HSC
N/A
The area under a velocity-time curve is the displacement, which in many cases, is the distance travelled.
 

braintic

Well-Known Member
Joined
Jan 20, 2011
Messages
2,137
Gender
Undisclosed
HSC
N/A
i was wondering where they got 2t2 in the bracket while integrating.
It could well have been 2t^2 - 6 (the displacement function). But after substituting and subtracting, the 6s cancel. Which is the reason you don't need a constant in the definite integral.

There wasn't actually any integration done, so it was a rather dumb way of setting it out. It would have been easier to say:
distance = x(5) - x(0) = 44-(-6) = 50

The note in the margin is actually rubbish. Method 2 would give exactly the same answer if the particle is oscillating, because the calculation is essentially the same. In this case, you would have to break the motion into separate domains with +ve and -ve velocities, and this would be a necessary and sufficient requirement for either method. I hope your teacher gave you an example of this.
 
Last edited:

D94

New Member
Joined
Oct 5, 2011
Messages
4,423
Gender
Male
HSC
N/A
I think they differentiated the displacement-time equation, which equals the velocity-time equation = 4t. Then they integrated that which = 2t^2, evaluated from t = 0 to t = 5.

Edit: too slow.
 
Joined
Oct 29, 2011
Messages
872
Location
Narnia
Gender
Female
HSC
2013
didn't you say distance was area under velocity curve? how could have they have used the displacement function.

edit: got answer from above
 
Joined
Oct 29, 2011
Messages
872
Location
Narnia
Gender
Female
HSC
2013
I have another question on distance. if anyone could help me.

what is the total distance travelled by x = 2sint-t from pi to zero. (using the second method).
and total distance travelled by the velocity curve 2-t from t1 to 2, and from 2 to t2 (answer is in terms of t1 and t2).
The the second question my only problem is setting out and not so much integrating and plugging in values.


anyone care to explain?? :)
 

ymcaec

Member
Joined
Apr 25, 2012
Messages
77
Gender
Undisclosed
HSC
N/A
I have another question on distance. if anyone could help me.

what is the total distance travelled by x = 2sint-t from pi to zero. (using the second method).
and total distance travelled by the velocity curve 2-t from t1 to 2, and from 2 to t2 (answer is in terms of t1 and t2).
The the second question my only problem is setting out and not so much integrating and plugging in values.


anyone care to explain?? :)





and the second one is similar - split it into two parts
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top