calculus question (1 Viewer)

[saltshaker]

Q15 (b)
should be easy enough

dx/dt = t
dy/dt = 1/t
dy/dx = 1/t^2

but the answer sheet says -1/t^2 ? Where did they get a bloody negative?

 

[saltshaker]

right after posting this just realised all tangents on your standard hyperbola will be of a negative gradient

but how was I meant to get that through calculus/algebraic manipulation?

 

[Drongoski]

dx/dt = c
dy/dt = -c/t^2

.: dy/dx = dy/dt / dx/dt = -c/t^2 / c = - 1/t^2

As you can see, you've got so many things wrong.

 

[saltshaker]

dx/dt = c
dy/dt = -c/t^2

.: dy/dx = dy/dt / dx/dt = -c/t^2 / c = - 1/t^2

As you can see, you've got so many things wrong.

what 'no parametrics in scope and sequence for yr11' does to a man

 

[CM_Tutor]

what 'no parametrics in scope and sequence for yr11' does to a man

The amount of parametrics included in the new syllabi is one area that is far from clear.